Lee Hom - Heartbeat

Monday, July 26, 2004

Gambling... open sourced?

Warning: If you think you do not have good self-control, please do not continue any further.

So what is this about? Basically, it is about a method that I used to use when I pay a visit to Genting's casino. Since I ain't having any luck in gambling, from the day I was borned, therefore I try to use a disciplined way when I go the gambling. While some of you might have realised about this method, however, this is a version for myself... =)

A disciplined way?

  • Method of gambling

  • First, it would be the method to use. Place the bet at 2^n and start with n=0. Until you win, increase n by 1 for the next bet. After you won, repeat your bet at n=0.
    Example:
    n=0, Bet value: 1 => Lose
    n=1, Bet value: 2 => Lose
    n=2, Bet value: 4 => Lose
    n=3, Bet value: 8 => Win

    repeat bet with n=0, therefore
    n=0, Bet value: 1 => ??

    While this method is surely a winning method, however, it is only true if we have an unlimited resource (or $$$). Therefore, for my level of discipline, I limit my stop point, that is after a certain consecutive round, I will stop increasing the n value but return back to n=0. If my stop point is n=3, therefore, I will stop to bet 16 on the next bet but return back to 1, if I happen to lose at n=3.

    So, how to imply it to the gambling table?

    Let's try it on Big/Small table. This method is better with higher winning percentage but the most we can get is by guessing the big or small result. Start to choose any of the two. Let's say we choose small and our bet is 2^n, with n=0, and therefore our bet is 1 (this is just the unit of bet, and not actual currency value. If you start with RM5, then 1 is matched to RM5, and therefore 2 would mean RM10, 2 x RM5).

    Let's say I lost at this bet. Continue my bet on the same result which, for my case, is still small at the moment. Now I should bet on small with 2, since 2^n with n=1 result in 2.

    Let's say I lost again at this bet. Continue my bet on the same result which, for my case, is still small at the moment. Now I should bet on small with 4, since 2^n with n=2 result in 4.

    Hopefully, I will win at this round or else my leg will be shaking when entering the next round, n=3.

    If I win, I will refresh the bet with n=0. If I lose, at n=3, I will also need to refresh the bet with n=0.

  • Patience

  • I realise that I will lose patient after an hour or two playing with this method, therefore, I need to have a discipline in patience too.


Actual Practice
I have actually practiced using the above method in real-life casino gambling, therefore I would like to share my experience here.

While this method can make me win, but I realised that I could only win about 100% from my initial investment. I couldn't exceed that point, to increase to 200%. After two to three hours of gambling, I lost everything back because the ghosts there is acting, and I lost my patience.

What actually happened? At that time, I bet on small but that counter showed big for more than 10 consecutive rounds!!

Can you believe that?! I can't...

While we can raise n to a bigger number, instead of 3, but the reason I limited it to 3 is because as n increased, the amount to bet will become bigger and bigger. If you realise from this method, we are actually winning only 1 unit for each win, no matter what is the value of n. Therefore, imagine putting 16 unit, with n=4, just to win a unit. It doesn't seems to worth the risk, right? Will you risk 16 unit just to win 1? This is surely not a good investment since the return rate is 1/16... =)

Try at your own risk and luck!!

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